Question

if 9^n×3^5×(27)^3by 3×(81)^4 = 27.find n​

Answer 1

Answer:

n = 3

Step-by-step explanation:

$\frac{9^{n} * 3^{5}*27^{3} }{3 * 81^{4} } = 27$

$9^{n}$ × 3 × 3 × 3 × 3 × 3 × 27 ×27 ×27   /   3 × 81 × 81 × 81 × 81     =  27

$9^{n}$ × 3 × 3 × 3 × 3 × 3  /  3 × 3 × 3 ×3 × 81                                   =  27

$9^{n}$ × 3   /  81                                                                                  = 27

$9^{n}$   / 27   =   27

$9^{n}$            =    27  × 27

$9^{n}$            =    3³ × 3³

$9^{n}$            =     $3^{6}$

$9^{n}$            =     $(3^{2} )^{3}$

$9^{n}$            =     9³

  n          =     3

Thank You :)

Answer 2

Answer:

-1

Step-by-step explanation:

{9^n×3^5× (27)^3 } ÷ {3×(81)^4} = 27

{(3²)^n×3^5×(3³)³ } ÷ { 3×(3⁴)⁴} = 3³

{ 3^2n × 3^5 × 3^9} ÷ {3× 3^8 } = 3³

{3^2n+5+9} ÷ 3^9 = 3³

3^2n+14 ÷3^9 = 3³

3^2n+14-9 = 3³

2n + 5 = 3

2n = 3-5

2n = -2

n = -2/2

n = -1