If 9 sin²θ + 5cos²θ = 6. Find tan θ
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Answer:
tanθ=1/√3
Step-by-step explanation:
9sin²θ+5cos²θ = 6
4sin²θ+5sin²θ+5cos²θ=6
4sin²θ+5(sin²θ+cos²θ)=6
4sin²θ+5(1)=6
4sin²θ+5=6
4sin²θ=6-5
4sin²θ=1
sin²θ=1/4
sinθ=(√1/4)
sinθ=1/2
sinθ=sin30°
θ=30°
tanθ=tan30°=1/√3
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