If 9 times 9th term of an arithmetic sequence is equal to 8 times 8th term find 17th term. How many term of these sequence makes sum 0
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Answer:
let 9th term be m and 8th term be n and 17th term be p
m = a + (9-1)d = a + 8d
n = a + (8-1)d = a + 7d
p = a + (17-1)d = a +16d
It is given
9m = 8n
9(a+8d) = 8((a+7d)
9a + 72d = 8a + 56d
9a - 8a + 72d - 56d = 0
a + 16d = 0 = 17th term
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