If 9 times the 9th term of an ap is equal to 13 times its 13th term ,show that the 22nd term of an ap is zero
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Answered by
67
9a9 = 13a13
9 (a + 8d ) = 13 (a + 12 d )
9a + 72d = 13a + 156d
9a - 13a = 156d - 72d
-4a = 82d
a = -41d / 2
a22 = a+ 21d
=- 41d/ 2 +21d
-41d +41d /2
= 0
9 (a + 8d ) = 13 (a + 12 d )
9a + 72d = 13a + 156d
9a - 13a = 156d - 72d
-4a = 82d
a = -41d / 2
a22 = a+ 21d
=- 41d/ 2 +21d
-41d +41d /2
= 0
Answered by
43
9a9 = 13a13
9 (a + 8d ) = 13 (a + 12 d )
9a + 72d = 13a + 156d
9a - 13a = 156d - 72d
-4a = 84d
a = -21d
a22 = a+ 21d
=- 21d +21d
= 0
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