If 9^x×3^2×(3-x/2)^-2=1/27,find x.
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Answer:
Given, 3
x
×27
x
=9
x+4
⇒3
x
×(3)
3x
=3
[2(x+4)]
⇒3
4x
=3
2(x+4)
.....Using a
m
×a
n
=a
m+n
As the bases are equal i.e. 3, their powers must be equal.
Therefore, 4x=2x+8
⇒2x=8
⇒x=4
Step-by-step explanation:
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