Question

If 9^x*3^5 *(27)^3÷3*81^4 =27 then find the value of x

Answer 1

HEYA!!!

9^x*3^5*27^3/3*81^4=27

=3^2x*3^5*3^9/3*3^16=3^3

=3^2x+5+9-3=3^3

=3^2x+11=3^3

=>2x+11=3

=>2x=3-11

=-8

=>x=-8/2

=-4

:. x=-4

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