if 9(x − y)^2
= 135 and x^
2 + y^
2 = 78, find the value of xy.
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Answer:
Step-by-step explanation:
9(x − y)^2 = 135
9(x^2 +y^2 -2xy) = 135
9x^2 + 9y^2 -18 xy = 135 equation 1
& x^2 + y^2 = 78
9x^2 + 9y^2 = 702
- ( 9x^2 + 9y^2 -18 xy = 135) (from equation 1)
---------------------------------------------
0 + 0 + 18xy = 567
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xy = 567/18 = 31.5
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