If 90, 146 and 230 are each divided by the same number, the remainder is 6. What is the greatest possible value of divisor?
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give numbers 90,140and230
remainder=6
for solving this question we need the concept of hcf
now 90-6=84
146-6=140
230-6=224
84=2*2*3*7
140=2*2*5*7
224=2*2*2*2*2*7
greatest possible number=hcf(84,140,224)
hcf=2*2*7=28
remainder=6
for solving this question we need the concept of hcf
now 90-6=84
146-6=140
230-6=224
84=2*2*3*7
140=2*2*5*7
224=2*2*2*2*2*7
greatest possible number=hcf(84,140,224)
hcf=2*2*7=28
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