Question

if 90 feet of fencing is required to enclose a rectangular service yard
whose width is two thirds its length, what are the dimensions of the
yard?​

Answer 1

Answer:

let

letw = the width of the rectangular service yard and w>0

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is length

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equations

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l2*(w + l) = 90

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l2*(w + l) = 90we find

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l2*(w + l) = 90we findl = 27 ft

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l2*(w + l) = 90we findl = 27 ftw = 18 ft

letw = the width of the rectangular service yard and w>0l = the length of the rectangular service yard and l>0width is two thirds is lengthw = (2/3)*l90 feet of fencing is required to enclose a rectangular service yard2*(w + l) = 90by solving the system of equationsw = (2/3)*l2*(w + l) = 90we findl = 27 ftw = 18 ftthe dimensions of the yard are 27 ft and 18 ft.

Answer 2

Answer:

length 27 fit

with 18 fit

Step-by-step explanation:

area of rectangle= (2L+2W).

2L+2W=90 eq(1)

width is 2/3 of length

width=2/3L put in eq (1)

then eq (1)

2L+2(2/3L) =90

2L+4/3L=90

10L/3=90

10L=90×3

10L= 270

L= 270÷10 p

L= 27 fit put in eq (1)

then

2(27)+W=90

54+2W=90

2w= 90-54

2w=36

w=36/2

width= 18 fit