Question

If α+β =90° and If If α+β =90° and α : β = 2:1 find the value of sinα : sinβ​

Answer 1

Answer:

√3

Step-by-step explanation:

as,

$\alpha + \beta = 90 \\ \alpha = 90 - \beta \\ or \\ \\ \frac{ \alpha \ \\}{ \beta } = \frac{2}{1}so \: put \: here \: the \: value \: of \: \: \\ \\ \alpha \: from \: above \\ so \\ \frac{90 - \beta }{ \beta } = \frac{2}{1} \\ by \: cross \: mupltiply \\ 90 - \beta = 2 \beta \\ 3 \beta = 90 \\ \beta = \frac{90}{3} \\ \beta = 30 \\ so \: from \: bove \\ \alpha = 90 - \beta \\ \alpha = 90 - 30 \\ \alpha = 60$

Answer 2

Answer:

$\alpha + \beta = 90 \\ \frac{ \alpha }{ \beta } = \frac{2}{1} \\ \alpha = 2 \beta \\ 2 \beta + \beta = 90 \\ 3 \beta = 90 \\ \beta = 30 \\ \alpha = 60 \\ \frac{ \sin( \alpha ) }{ \sin( \beta ) } = \frac{ \sin(60) }{ \sin(30) } = \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} } = \frac{ \sqrt{3} }{1}$

Hope its help uh...❤