Question

If 96500 coulomb of electricity is passed through CuSO4 solution, it will liberate

Answer 1

At the cathode

Cu2+ (aq) + 2e-  ---> Cu(s)

At the anode4OH-(aq) ----> 2H2O (l) + O2(g) + 4e-

Faraday’s constant = 96500C/mol

To deposit 1 mole of copper, we need 2x96500CSo, 96500C will deposit 0.5 moles of copper = 0.5x63.5 = 31.75g

To liberate one mole of oxygen molecules,we need  4x96500CSo, 96500C will liberate = ¼  = 0.25 moles = 0.25x32 = 8g

Answer 2

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