Question

If 98 cm,5 cm and 45 cm are the sides of a triangle,then its semiperimeter will be?​

Answer 1

$s = \frac{a + b + c}{2}$

$s = \frac{98 + 5 + 45}{2}$

$s = \frac{148}{2}$

$s = 74 \: {cm}$