If 98215x2 is divisible by 4.Then find all values of x.
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If the no. formed by the last two digits of a number is divisible by 4, then so will be that number.
100x + 10y + z will be divisible by 4 if 10y + z is divisible by 4, for any positive integer x and for any one-digit positive integers y and z.
If 98215x2 is divisible by 4, then so will be x2.
Two digits multiples of 4 ending in 2 are: 12, 32, 52, 72, 92.
Thus the possible values of x are 1, 3, 5, 7 and 9.
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