Math, asked by princeimran3635, 1 year ago

if 9999=4, 8888=8, 1816=6, 1212=0, then 1919=?

Answers

Answered by avinashsingh48
0
1919 = 2

\bf\green{step\ by\ step\ explaination}

it depends on zeroes

such in first

9999 = 4

because , there are 4 zeroes in 9999

in second

8888. = 8

because ,there are 8 zeroes , two zeroes in all 8

in third question

1816 = 3. (sorry here Will be three instead of 6)

because there are 3 zeroes , two in 8 and one in 6.


in forth question

1212 = 0

because there are none zero in any digit


and then in fifth question

1919 = 2

because there are two zeroes , one in 9 and another is also in 9




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I hope that this helpful for you so please make me brainliest.

Answered by Iiivveee
0

Answer:


Step-by-step explanation:

It's more logical.

9999=4 therefore a 9=1

8888=8 therefore an 8=2

1212=0

1919=?

We have two nines already making 2 and one is a bit tricky but after come contemplating i decided 1=1 bacause it's a really solid number. The answer to 1919 is 4

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