If 9kg of food contains 25000 calories, how many kg of food will contain 5000 calories?
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Answer:
Let x kg be the food containing 5000 calories
9 kg food contains 25000 calories
Therefore, 9 = 25000
x = 5000
Therefore by closs multiplication we get
25000x= 9×5000
x = 9×5000/25000
x= 9/5
x = 1.8
Therefore 1.8 kg food will contain 5000 calories
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