Question

if 9n×3 2 ×3n-(27)n
______________
(3 3)5 ×(2)3
1/27 find the value of n​

Answer 1

Answer:

Given (9n × 32 × 3n – (27)n)/ (33)5 × 23 = (1/27) = (32)n × 33 × 3n – (33)n/ (315 × 23) = (1/27) = 3(2n+2+n) – (33)n/ (315 × 23) = (1/27) = 3(3n+2)– (33)n/ (315 × 23) = (1/27) = 33n × 32 – 33n/ (315 × 23) = (1/27) = 33n × (32 – 1)/ (315 × 23) = (1/27) = 33n × (9 – 1)/ (315 × 23) = (1/27) = 33n × (8)/ (315 × 23) = (1/27) = 33n × 23/ (315 × 23) = (1/27) = 33n/315 = (1/27) = 33n-15 = (1/27) = 33n-15 = (1/33) = 33n-15 = 3-3Read more on Sarthaks.com - https://www.sarthaks.com/682795/if-9-n-3-2-3-n-27-n-3-3-5-2-3-1-27-find-the-value-of-n