Question

If 9sec A= 41, find cos A and cot A.​

Answer 1

the value of cosA 9/41 and cotA9/40

Answer 2

Answer:

Step-by-step explanation:

rearranging we get,

Sec A = 41/9

Cos A = 1/Sec A

=9/ 41 ANS

by pythagoras theorm

41^2=9^2 + x^2

1681 = 81 + x^2

1600 = X^2

x = 40

Now  cot A = 9/40