if 9th term of an a.p is 0 ,prove that its 29 th term is double the 19th term.
Answers
Answered by
3
Hii ☺ !!
Given :-
9th term = 0
a + 8d = 0
a = -8d
To prove :-
29th term = 2 ( 19th term)
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 2 ( 10d )
20d = 20d
LHS = RHS........PROVED......
Given :-
9th term = 0
a + 8d = 0
a = -8d
To prove :-
29th term = 2 ( 19th term)
a + 28d = 2 ( a + 18d )
-8d + 28d = 2 ( -8d + 18d )
20d = 2 ( 10d )
20d = 20d
LHS = RHS........PROVED......
Answered by
0
Answer:
Let the first term ot hte a. p. =a and the common difference = d t9= 0
t9 = a+ 8d =0
a=-8d
and
t19= a+ 18d
=-8d+18d
t19=10d............................1
and
t29=a+28d
=-8d+28d
=20d
t29=20d..................................2
hence from 1&2
it is proved
Step-by-step explanation:
Muraja:
thanks
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