if 9th term of an AP is 0 prove that 29th term is double of 19 th term
Answers
Answered by
0
Answer:
T9=a+8d
a=-8d
where
T29=2×a+18d
a+28d=2×-8d+18d
-8d+28d=2×10d
20d=20d
proved
Answered by
0
Answer:
9th term = a+(9-1)d
ATQ, 9th term is 0
so, 0=a+8d
a=-8d (i)
29th term will be
=a+(29-1)d
=a+28d
from i a=-8d
=-8d+28d
=20d
19th term= a+18d
= -8d+18d
=10d
HENCE
20D=2*10D
29TH TERM=2*19TH TERM
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