Question

if 9th term of an AP is 0 then the ratio of its 19th and 29th term is ?

Answer 1

Answer:

Here it goes

Step-by-step explanation:

$Given = a_{9} = 0\\\\ i.e  a + 8d = 0\\\\ 8d = a --> 1\\\\  \frac{a_{19}}{a_{29} } = \frac{a+18d}{a+28d} \\\\ = \frac{4d + 18d}{4d+28d}\\\\  = \frac{22d}{32d} \\\\ =\frac{11}{16}$

i.e 11:16