Question

if 9th term of an AP is zero,prove that its 29th term is twice the 19th term.​

Answer 1

Let a and d respectively be the first term and common difference of the AP.

Given a9 = 0

So, a + (9-1)d = 0

a+8d=0

a= -8d

 

Now, 29th term = a+28d

=-8d+28d

= 20d = 2 x 10d

= 2(-8d + 18d)

=2(a+18d)

= 2 x 19th term

Thus, the 29th term of the AP is twice the 19th term.

Hope this helps!

Answer 2

Answer:

Step-by-step explanation:

Pl check the solution in attachment