Question

If 9x^2+25y^2=181 and xy = -6, find the value of 3x+5y. please answer for solution​

Answer 1

$9x^2+25y^2=181\\=>9x^2+30xy+25y^2=181+ 30*(-6)\\=>(3x+5y)^2=181-180\\=>(3x+5y)^2=1\\=>3x+5y=1 or -1$

Answer 2

$\huge\boxed {Answer}$

Given :-

9x² + 25y² = 181

Also xy = -6

To Find out :-

Value of (3x + 5y)

Formula :-

(a + b) = √(a² + 2ab + b²)

Explanation :-

(3x + 5y) = √(3x)² + 2(3x)(5y) + (5y)²

= √(9x² + 30xy + 25y²)

= √(9x² + 25y² + 30xy)

= √(181) + 30(-6)

= √181 - 180

= √1

= 1

Result :-

Value of (3x + 5y) = 1