If
9x^2+y^2= 58 , xy=7
Then
3x+y=?
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Hi friend,
Please refer the pic.
Hope it helps..!!!!
Please refer the pic.
Hope it helps..!!!!
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Answered by
1
9x² + y² = 58
xy = 7 { given
we know (a+b)² = a²+b²+2ab
use it here
(3x)²+y² = 58
we can write it as
(3x+y)² - 2(3x)(y) = 58
put value of xy
=> (3x+y)² - 6(7) = 58
=(3x+y)² = 58+42
= (3x+y)² = 100
taking square root both side we get
3x+y = 10
xy = 7 { given
we know (a+b)² = a²+b²+2ab
use it here
(3x)²+y² = 58
we can write it as
(3x+y)² - 2(3x)(y) = 58
put value of xy
=> (3x+y)² - 6(7) = 58
=(3x+y)² = 58+42
= (3x+y)² = 100
taking square root both side we get
3x+y = 10
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