Question

If 9x+2y^2-3z^2=132 and 9y+2y^2-3z^2=-12, then x-y=
a) 3 b) 8 c) 16 d) 120 E) 144

Answer 1

Step-by-step explanation:

if 9x + 2y^2 - 3z^2 = 132 and 9y + 2y^2 - 3z^2 = -12

now subtract them

9x + 2y^2 - 3z^2 = 132 - 9y + 2y^2 - 3z^2 = - 12

9x - 9y = 144

x-y = 144/9/9/

x-y = 144

Answer 2

Answer:

x-y=16

Step-by-step explanation: