Math, asked by faizalmalik5635, 1 year ago

If 9x square + kx + 1 = 0 find equal roots

Answers

Answered by muskan0016
12
9x2+kx+1=0 ,a=9 b=k c=1

for equal roots D=0 or b2-4ac =0

k2-4(9)(1)=0

k2=36
k=root36
k=+6 or -6
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Answered by madhu1431
2

from roots formula

b^2-4ac

b=k

A=9

C=1

k^2-4×9×1=0

k^2-36=0

k^2=36

k=root36

k=6

hope you understand

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