if 9x2+kx+1=0 has equal roots then find the value of k
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5
Answer:
The given equation if 9x
2
+kx+1=0
comparing with ax
2
+bx+c=0
here a=9, b=k , c=1
△ = b
2
−4ac
= k
2
−4(9)(1)
= k
2
−36
The roots are equal so △ must be zero
∴ = k
2
−36=0
= (x+6)(x−6)=0
=x+6=0 or x−6=0
∴ k=−6 or k=6
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2
hope it helps
good day
purple ya
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