Question

if 9xpower4+12xcube+28xsquare+ax+b is a perfect square. then find the values of a and b

Answer 1

Answer:

it is not a perfect square,

9*9^4+12*the cube+28*square+ax+b=14,077

9^4=6561

9*9^4+12=9*6561+12

(9*6561)+12=59,049+12=59,061

59,061*12 the cube+28 the square+ax+b=14,077

the square root of 787 is 28.0535 etc

28.0535 etc*28.0535 etc=787.999 etc

therefore it is not a perfect square.

59,061*12=708,732

708,732+28+ax+b=14000+8+32+28+ax+b=14,077

14040+(1*25)+2=14040+25+2=14,077