Question

If
a: 0.00053 x 10 (-12)
and b=0.0324 x 10 (-5)
then find i. a+b
ii. b-a​

Answer 1

Step-by-step explanation:

$0.00053 \times {(10)}^{ - 12} = \frac{0.00053}{ {(10)}^{12} } \\ \\ = \frac{53}{100000 \times 1000000000000 } \\ \\ = \frac{53}{100000000000000000} \\ \\ = 0.00000000000000053 \\ \\ now \: \: 0.0324 \times {(10)}^{ - 5} \\ \\ = \frac{324}{10000 \times {(10)}^{5} } \\ \\ = \frac{324}{1000000000} \\ \\ = 0.000000324 \\ \\ now \: \: \: a + b = 0.00000000000000053 + 0.000000324 \\ \\ = 0.00000032400000053 \\ \\ now \: b - a = 0.000000324 - 0.00000000000000053 \\ \\ = 0.00000032399999947 \\ \\ this \: is \: ur \: required \: answer$

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