Question

If A={0,2,4}then find A=null set A union null set A intersection A what do you observe from the result​

Answer 1

Answer:

Correct option is

A

A is singular

B

B is singular

Let B be non-singular, then B−1 exists.

Now, AB=0( given)⇒(AB)B−1=0B−1

( post multiplying both sides by B−1)

⇒A(BB−1)=0     ( by associativity )

⇒AIn=0(∵BB−1=In)

⇒A=0

But A is a non-null matrix.

Hence B is a singular matrix.

Similarly, it can be shown that A is a singular matrix.

Step-by-step explanation:

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