Science, asked by OURcomrade, 1 day ago

if a 0.2 kg ball is thrown with a velocity of 3.2 m/s what is its KE

Answers

Answered by steffiaspinno
0

Answer:

Explanation:

We know that K.E = \frac{1}{2}mv^{2}

Here, m=0.2 kg

and v = 3.2 m/s

so K.E =  \frac{1}{2}x0.2x3.2^{2}

Therefore K.E = 1.024 J

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