Question

If a = 0.24 and b = 1.76, then compute the following expression. a^4 + 4ab^3 + 6(a^2)(b^2) + 4ab^3 + b^4

Answer 1

Answer:  The value of this expression is 21.14.

Explanation :

Since we have given that

a = 0.24 and b = 1.76

Now, we have the expression i.e.

$a^4+4ab^3+6a^2b^2+4ab^3+b^4$

For computation, we substitute the value of a and b in the given expression,

$a^4+4ab^3+6a^2b^2+4ab^3+b^4\\\\=0.24^4+4\times 0.24\times 1.76^3+6\times 0.24^2\times 1.76^2+4\times 0.24\times 1.76^3+1.76^4\\\\=21.136384$

Hence, the value of this expression is 21.14.

Answer 2

Answer:

(a+b)^4= a^4 + 4(a^3)b + 6(a^2)(b^2) + 4a(b^3) + b^4

so the solution is (a+b)^4

=(.24+1.76)^4

=2^4

=16

ANSWER IS 16

Step-by-step explanation: