If a 0.2800 g of sample of Sodium Bicarbonate (96.5% NaHCO3) is titrated with 0.9165N Sulfuric Acid, what volume of the acid would be required to produce an endpoint?Show your solutions, thanks.
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Answer: 3.51 ml
Step-by-step explanation:
% = V × N × MeWT / Sample weight
Volume is missing :
96.5% = (V?) × 0.9165N × 0.08041 ÷ 0.2800 g
= 0.9165N / 96.5 % × 0.2800 g
= 0.9165N / 0.2702
= 3.39 ml
Since 3.39 ml is not enough. Adjust the volume into 3.51 ml
Lets Check :
% = V × N × MeWT / Sample weight
= 3.51 × 0.9165N × 0.08041 / 0.2800 g
= 96.5 % (Round off)
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