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If A = 0,
and f:A --В, f(x) = cosx is surjесtiоn find B.
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Answer:
Injectivity : We know that f(0)=cos0=1 and f(2π)=cos2π=1.
So, different elements in R may have the same image. Hence, f is not an injection.
Surjectivity : Since the values of cosx lie between −1 and 1, it follows that the range of f(x) is not equal to its co-domain. So, f is not a surjection.
Step-by-step explanation:
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