Question

if a=0,b=1,c=b+a,d=c+b, and so on find the sum of the alphabets of agiven word that is "Man"

Answer 1

Answer:

a = 0

b = 1

c = 1.

m. 144

n. 233

144 +0 + 233

= 377

Answer 2

Answer:

Required value of Man is 377.

Explanation:

Given,a=0,b=1,c=b+a,d=c+b

According to sequence,

$e = d + c \\ = 1 + 2 \\ = 3$

and

$f = e + d \\ = 3 + 2 \\ = 5$

and

$g = f + e \\ = 5 + 3 \\ = 8$

So,

$h = 13 \\ i = 21 \\ j = 34 \\ k = 55 \\ l = 89 \\ m = 144 \\ n = 233$

So,

$man = 144 + 0 + 233 \\ =377$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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