Question

If a = 0, b = -1, then the value of 2a²b + 2ab2 + ab is ( step by step )​

Answer 1

Answer:

☞ Given,

☆ a = 0

and

☆ b = - 1

so

$2 {a}^{2} b + 2a {b}^{2} + ab \\ \\ = 2 {(0)}^{2} ( - 1) + 2(0) {( - 1)}^{2} + 0 \times ( - 1) \\ \\ = - 2 + 2 \times 0 + 0 \\ \\ = - 2 + 0 + 0 \\ \\ = - 2$

# keep smiling ☺

Answer 2

$\huge\underline\mathrm\color{cyan}{ANSWER}$

Given:

a = 0 b = -1

To find :

2a²b + 2ab² + ab

Solution :

2a²b + 2ab² + ab

Substituting the given values we get

=> 2×(0)²×(-1) + 2×(0)×(-1)² + 0×(-1)

=> 2×0×-1 + 2×0×1 + 0

=> 0 + 0 +0

=> 0

Points to remember :

• Square of a negative number gives a positive number.
• Product of any integer and zero is zero itself.