Question

if A=0 , B=30,C=45,D=60,E=90, Prove that tan^2A+tan^2B+tan^2C+tan^D=13/3​

Answer 1

A = 0 = 0

B = 30 = 1/√3

C = 45 = 1

D = 60 = √3

E = 90 = not defined.

Expression:-

= tan²A + tan²B + tan²C + tan²D

= (0)² + (1/√3)² + (1)² + (√3)²

= 0 + 1/3 + 1 + 3

= 1+ 3 + 9/3

= 13/3

Hence, Proved