Question

If a=0,b=9908,c=(-298) tjen axb+c+c-a=?​

Answer 1

Answer:

-596

Step-by-step explanation:

0*9908=0

-298+-298=-596

-0=0

final =-596

Answer 2

Answer:

a=0, b=9908, c=(-298).

a×b+c+c-a=?.

substituting a,b & c values.

0×9908+(-298)+(-298)-0.

0-298-298-0.

-298-298.

-596.

I think this is your answer.