If a=0,b=9908,c=(-298) tjen axb+c+c-a=?
Answers
Answered by
1
Answer:
-596
Step-by-step explanation:
0*9908=0
-298+-298=-596
-0=0
final =-596
Answered by
1
Answer:
a=0, b=9908, c=(-298).
a×b+c+c-a=?.
substituting a,b & c values.
0×9908+(-298)+(-298)-0.
0-298-298-0.
-298-298.
-596.
I think this is your answer.
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