Question

If a≠0, then show that
$\frac{ {a}^{2} + 1 } { \sqrt[a]{( \frac{ {a}^{2} - 1}{2a} } )^{2} } = 2 \: or \: - 2$
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Answer 1

Answer:

x 1 = − b + b 2 − 4 a c 2 a and x 2 = − b − b 2 − 4 a c 2 a {\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{ 2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2 }-