If A(-1,0), B(5,-2), and C(8,2) are the vertices of a Triangle ABC, then the centroid is *
1 point
(4,0)
(-4,4)
(0,4)
(4,-4)
Answers
Answer:
see the attachment for answer
Step-by-step explanation:
your final answer is-
Centroid is (4,0) .
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Given : A(-1,0), B(5,-2), and C(8,2) are the vertices of a Triangle ABC
To find : centroid of triangle
Solution:
in Any triangle
where vertex of triangle are (x₁ , y₁) , (x₂ , y₂) & (x₃ , y₃)
then centroid of triangle = (x₁ + x₂ + x₃)/3 , (y₁ + y₂ + y₃)/3
A(-1,0), B(5,-2), and C(8,2)
Centroid of Triangle = ( -1 + 5 + 8)/3 , ( 0 - 2 + 2)/3
= (12)/3 , 0/3
= 4 , 0
(4,0) is the centroid of triangle ABC If A(-1,0), B(5,-2), and C(8,2) are the vertices
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