Question

If A(-1,0), B(-5, 2) and C(8, 2) are the vertices of a triangle ABC then its centroid is
(b) (6,0)
(C) (4,0)
(d) (0,6)
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Answer 1

Answer:

(6,0) (4,0) (0,6)

=(6,0) (4,0)

=√(x2-x1)2+(y2-Y1)2

=√(4-0)2+(0-6)2

=√(4)2+(6)2

=√16+36

=√52

=16√36

(4,0)(0,6)

=√(0-4)2+(6-0)2

=√(4)2+(6)2

=√16+36

=√52

(0,6)(6,0)

=√(6-0)2+(0-6)2

=√(6)2+(6)2

=√36+36

=√72