If A={-1,1} B={0,2} c={0,1} then find (A×B) ^ (B×C).
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A={0,1}
B={1,2,3}
A×B={(0,1),(0,2),(0,3),(1,1),(1,2),(1,3)}
B×A={(1,0),(2,0),(3,0),(1,1),(2,1),(3,1)}
By the definition of equality of ordered pairs, the pair (0,1) in A×B is not equal to the pair (1,0) in B×A
Therefore, A×B
=B×A
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