If A = {-1,1},FIND A*A*A
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A*A*A={-1,1}*{-1,1}*{-1,1}
A*A*A={-1,-1,-1} ; {-1,-1,1} ; {-1,1,-1} ; {-1,1,1} ; {1,-1,-1} ; {1,-1,1} ; {1,1,-1} ; {1,1,1}
A*A*A={-1,-1,-1} ; {-1,-1,1} ; {-1,1,-1} ; {-1,1,1} ; {1,-1,-1} ; {1,-1,1} ; {1,1,-1} ; {1,1,1}
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Answer:
It is known that for any non-empty set A, A x A x A is defined as
A x A x A = {(a,b,c): a,b,c ∈ A}
It is given that A = {-1,1}
Therefore
A x A x A = {-1,-1,-1} , {-1,-1,1} , {-1,1,-1} , {-1,1,1} , {1,-1,-1} , {1,-1,1} , {1,1,-1} , {1,1,1}
Hope it Helps!
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