if A= (-1,1) so find A³
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4A.
solutions.
A³ = A×A×A
[ 1 -1, -1 1]
A×A = [ 1 -1, -1 1] × [ 1 -1, -1 1 ] = [ 1+1. -1-1, -1-1. 1+1]
= [ 2 -2, -2. 2]
= 2x [ 1 -1, -1 1] = 2A
A³ =. A×A×A = 2A×A = (A×A) = 2x (2A) = 4A
answers. 4A.
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