If a = 1/10
and b = −3/8 then which one of a + b, a- b, a × b, a ÷ b is the
smallest ? Show the method
Answers
Answered by
1
Step-by-step explanation:
A∪B={1,2,3,8}
A∩B={3}
∴(A∪B)×(A∩B)
={(1,3),(2,3),(3,3),(8,3)}
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Answered by
0
Step-by-step explanation:
a+b=1/10-3/8=-22/80=-11/40
a-b=1/10+3/8=19/40
a×b=-3/80
a/b=1/10×-8/3=-8/30
rationalize and u will get that a+b is smallest
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