Question

if a=[1-11-1] b=[a-1b-1] if (A+b)²=A²+B² find a and b

Answer 1

Step-by-step explanation:

a= -11 ,

b= a - b -1 ===== 2b= a- 1

b= -12/2= -6

hope it will help

Answer 2

Proving L.H.S ≠ R.H.S

Step-by-step explanation:

$\ Given \ value:\\\\a= [1-11-1]\\\\b=[a-1b-1]\\\\\ find:\\\\(a+b)^2= a^2+b^2 \\\\\ Solution:\\\\a= [1-11-1]\\\\b=[(a-1)(b-1)]\\\\a= [1-12]\\\\ \rightarrow a=[ -11]\\\\b= [a-1b-1]\\\\\rightarrow b= [(a-b-1)]\\\\ \rightarrow b=[-b-12] \\\\ \rightarrow b=-b-12 \\\\ \rightarrow \ 2b=-12 \\\\ \rightarrow \ b= -6 \\\\ \ proving: \\\\ (a+b)^2= a^2+b^2 \\\\\ formula:\\\\(a+b)^2 = a^2+b^2+2ab\\\\ \ Solve \ L.H.S \\\\(-11 + (-6))^2$

$\rightarrow (-11 -6)^2\\\\\rightarrow (-17)^2\\\\\rightarrow 289$

$\ Solve \ R.H.S \\\\(-11)^2 + (-6)^2 \\\\\rightarrow 121 + 36 \\\\\rightarrow 157$

L.H.S≠ R.H.S

Learn more:

• Proving: https://brainly.in/question/8157059