If A=
1 2
0
1
then An =
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1
Answer:
The product of lower triangular matrices is again lower triangular and on the diagonal they have the products of the diagonal elements.
Thus each power will have 1 on the diagonal and 0 at the top right corner. It suffices to determine the bottom left corner. Set
An=[1xn01]
with x1=1 . We want to exploit the recursive definition of power, so
[1xn+101]=An+1=AnA=[1xn01][1101]=[1xn+101]
and therefore xn+1=xn+1 . This clearly implies xn=n , so finally
An+1=[1n01]
Now try with
F=[0111]
It will be fun.
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