Math, asked by pallavisavarkar9, 8 months ago

if A= [1 2/-1 -2] B=[2 a/-1 b] a(a+B)^2 =a+b^2 find the value of A&B​

Answers

Answered by okr9861
3

Answer:

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Answered by shameetdamle
0

Answer:

Step-by-step explanation:

Firstly , rationalize the denominator of the LHS....

√2 - 1 / √2 + 1

= (√2 - 1 / √2 + 1) × ( √2 - 1 / √2 - 1)

= ( √2 - 1 )^2 / (√2)^2 - (1)^2

= [ (√2)^2 + (1)^2 - 2*√2*1 ] / 2 - 1

= (2 + 1 - 2√2) / 1

= 3 - 2√2

We know that ,,

=> 3 - 2√2 = a + b√2

So,

a = 3

b = - 2

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