Question

if A [ 1/2,3/4] find the value of B
When A2+ 2A+ B=0
​

Answer 1

Answer:

Given, A=[21−12] Now, A2=[21−12][21−12]=[4−12+2−2−2−1+4]

⇒ A2=[34−43]

Now, A2+2A−3l=[34−43]+2[21−12]−3[1001]

=[3+4−3−4−2−04+2−03+4−3]=[46−64]