Question

if a=1/2+√3 and b=1/2-√3 then ab=​

Answer 1

Answer:

Clearly ab= 1/(2^2–3) = 1. So ab=1. By rationalizing we get a= 2+3^(1/2) —»a^2= 4+3+4*3^(1/2)= 7+4*3^(1/2). -By Substituting a^2 and ab values in 7a^2+11ab we..

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• If $a=\frac{1}{2+\sqrt{3}}$ and $b=\frac{1}{2-\sqrt{3}}$,find $ab$.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

Given,

$a = \frac{1}{2 + \sqrt{3} }$

$b = \frac{1}{2 - \sqrt{3} }$

Therefore,

$ab = \frac{1}{2 + \sqrt{3} } \times \frac{1}{2 - \sqrt{3} }$

$= \frac{1}{ {(2)}^{2} - {( \sqrt{3}) }^{2} }$

$= \frac{1}{4 - 3}$

$= \frac{1}{1}$

$= 1$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• $ab = 1$