Math, asked by himanshukalal, 11 months ago

if a=1/(2-√3) and b= 1/(2+√3) then what is the value of 7a^2+11ab ?​

Answers

Answered by kritika9658
1

Answer:

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Answered by gyani42
0

7a^2+11ab

Now put the of a and b

=7(2-√3)^2+11{(2-√3)(2+√3)}

=7(4-4√3+3)+11{(2)^2-(√3)^2}

=(28-28√3+3)+11(4-3)

=(31-28√3)+11

=3√3+11

=14√3

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